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6k^2-90=-12k
We move all terms to the left:
6k^2-90-(-12k)=0
We get rid of parentheses
6k^2+12k-90=0
a = 6; b = 12; c = -90;
Δ = b2-4ac
Δ = 122-4·6·(-90)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-48}{2*6}=\frac{-60}{12} =-5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+48}{2*6}=\frac{36}{12} =3 $
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